X^2-6x+1.89=0

Solution for X^2-6x+1.89=0 equation:

X^2-6X+1.89=0

a = 1; b = -6; c = +1.89;
Δ = b2-4ac
Δ = -62-4·1·1.89
Δ = 28.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{28.44}}{2*1}=\frac{6-\sqrt{28.44}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{28.44}}{2*1}=\frac{6+\sqrt{28.44}}{2}
$